Before starting the program ,make sure that you have completed your looping concept of programming . If you not completed yet then visit by clicking here LOOP PROGRAMMING CONCEPT.
learn switch case statement
 |
| A step up programming |
You can modify these programming by your own concept.
P1. Program to print the given pattern :-
 |
| P1. Pattern in c |
#include<stdio.h>
#include<conio.h>
void main()
{
int i , j ;
for ( i = 1 ; i
<= 5 ; i ++ )
{
for ( j = 1 ; j
<= 5 ; j ++ )
{
if ( j <= i )
printf ( “ * “
);
else
printf (
“ “ );
}
printf ( “ \n “ );
}
getch ();
}
P2. Program to print the given pattern :-
 |
| P2. Pattern in c |
#include<stdio.h>
#include<conio.h>
void main()
{
int i , j ;
for ( i = 1 ; i
<= 5 ; i ++ )
{
for ( j = 1 ; j
<= 5 ; j ++ )
{
if ( j >= 6-i )
printf ( “ * “
);
else
printf (
“ “ );
}
printf ( “ \n “ );
}
getch ();
}
P3. Program to print the given pattern :-
 |
| P3. Pattern in c |
#include<stdio.h>
#include<conio.h>
void main()
{
int i , j ;
for ( i = 1 ; i
<= 5 ; i ++ )
{
for ( j = 1 ; j
<= 5 ; j ++ )
{
if ( j >= i )
printf ( “ * “
);
else
printf (
“ “ );
}
printf ( “ \n “ );
}
getch ();
}
P.4 Program to print the given pattern :-
 |
| P4. Pattern in c |
#include<stdio.h>
#include<conio.h>
void main()
{
int i , j ;
for ( i = 1 ; i
<= 5 ; i ++ )
{
for ( j = 1 ; j
<= 5 ; j ++ )
{
if ( j <= 6-i )
printf ( “ * “
);
else
printf (
“ “ );
}
printf ( “ \n “ );
}
getch ();
}
P.5 Program to print the given pattern :-
 |
| P5. Pattern in c |
#include<stdio.h>
#include<conio.h>
void main()
{
int i , j ;
for ( i = 1 ; i
<= 5 ; i ++ )
{
for ( j = 1 ; j
<= 9 ; j ++ )
{
if ( j >= 6-i
&& j <= 4+i )
printf ( “ * “
);
else
printf (
“ “ );
}
printf ( “ \n “ );
}
getch ();
}
P.6 Program to print the given series :-
 |
| P6. Pattern in c |
#include<stdio.h>
#include<conio.h>
void main()
{
int i , j , k ;
for ( i = 1 ; i
<= 5 ; i ++ )
{
k=1;
for ( j = 1 ; j
<= 9 ; j ++ )
{
if ( j >= 6-i
&& j <= 4+i && k )
{
printf ( “ * “
);
k = 0;
}
else
{
printf (
“ “ );
k = 1 ;
}
}
printf ( “ \n “ );
}
getch ();
}
P.7 Program to print the given pattern :-
 |
| P7. Pattern in c |
#include<stdio.h>
#include<conio.h>
void main()
{
int i , j ;
for ( i = 1 ; i
<= 5 ; i ++ )
{
for ( j = 1 ; j
<= 9 ; j ++ )
{
if ( j <= 6-i
|| j >= 4 + i)
printf ( “ * “
);
else
printf (
“ “ );
}
printf ( “ \n “ );
}
getch ();
}
P.8 Program to print the given pattern :-
 |
| P8. Pattern in c |
#include<stdio.h>
#include<conio.h>
void main()
{
int i , j , k ;
for ( i = 1 ; i
<= 4 ; i ++ )
{
k=1;
for ( j = 1 ; j
<= 7 ; j ++ )
{
if ( j >= 5-i
&& j <= 3+i )
{
printf ( “ %d “
, k );
j<4?k++:k--;
}
else
printf (
“ “ );
}
printf ( “ \n “ );
}
getch ();
}
P.9 Program to print the given pattern :-
 |
| P9. Pattern in c |
#include<stdio.h>
#include<conio.h>
void main()
{
int i , j ;
char k ;
for ( i = 1 ; i
<= 4 ; i ++ )
{
k = ‘A’ ;
for ( j = 1 ; j
<= 7 ; j ++ )
{
if ( j <= 5-i
|| j >= 3+i )
{
printf ( “ %c “
, k );
j <4 ? k++
: j-- ;
}
else
{
printf (
“ “ );
if ( j == 4 )
k--;
}
}
printf ( “ \n “ );
}
getch ();
}
P.10 Program to print the given pattern :-
 |
| P10. Pattern in c |
#include<stdio.h>
#include<conio.h>
void main()
{
int i , j , k = 0;
for ( i = 1 ; i
<= 7 ; i ++ )
{
i <= 4 ? k++ :
k-- ;
for ( j = 1 ; j
<= 7 ; j ++ )
{
if ( j >= 5-k
&& j <= 3+k )
printf ( “ * “
);
else
printf (
“ “ );
}
printf ( “ \n “ );
}
getch ();
}
If You want more pattern program like this then follow my blog and comment below .
share this blog to the needed person.
There are lots of more pattern like this which was updated later, so connect with us.
Basic concept of programming
More uderstanding program
